if the points A (X, 2) B( - 3 ,- 4( and C (7 ,- 5) are collinear then find x.?
shivaniverma29:
hii piyush
Answers
Answered by
25
Hey Mate ❤️❤️❤️
your answer is.......
The given points are A(x, 2) , B(-3, -4) and C(7, -5).The points A, B and C are collinear if area of a triangle formed by joining these points is 0.
so, area of Δ ABC = 0
⇒12[x1(y2−y3) + x2(y3−y1) + x3(y1−y2)] = 0
⇒12[x(−4+5)−3(−5−2) +7(2+4)] = 0
⇒12[x − 3(−7)+ 7×6] = 0
⇒12[x+21+42] = 0
⇒12[x+63] = 0
⇒x+63 = 0
⇒x = −63
hope this answer helps you
please mark it as brainliest ✌️✌️✌️✌️
your answer is.......
The given points are A(x, 2) , B(-3, -4) and C(7, -5).The points A, B and C are collinear if area of a triangle formed by joining these points is 0.
so, area of Δ ABC = 0
⇒12[x1(y2−y3) + x2(y3−y1) + x3(y1−y2)] = 0
⇒12[x(−4+5)−3(−5−2) +7(2+4)] = 0
⇒12[x − 3(−7)+ 7×6] = 0
⇒12[x+21+42] = 0
⇒12[x+63] = 0
⇒x+63 = 0
⇒x = −63
hope this answer helps you
please mark it as brainliest ✌️✌️✌️✌️
Answered by
18
hEyA here u go......
Eq for line BC.....
x1=-3..........y1=-4
x2=7...........y2=-5
slope=(y2-y1)/(x2-x1)=(-5+4)/(7+3)=-1/10
equation...=y-y1=slope(x-x1)
y+4=(-1/10)*(x+3)
10y+40=-x-3
x+10y=-43.....①
coordinates of A=(x,2)
as the lines are collinear so value of x=x and y=2 will satisfy the eq.①
x+10*2=-43
x+20=-43
x=-63
hope it helps you ......
plz mark as brainliest.....
Eq for line BC.....
x1=-3..........y1=-4
x2=7...........y2=-5
slope=(y2-y1)/(x2-x1)=(-5+4)/(7+3)=-1/10
equation...=y-y1=slope(x-x1)
y+4=(-1/10)*(x+3)
10y+40=-x-3
x+10y=-43.....①
coordinates of A=(x,2)
as the lines are collinear so value of x=x and y=2 will satisfy the eq.①
x+10*2=-43
x+20=-43
x=-63
hope it helps you ......
plz mark as brainliest.....
Similar questions