If the points A (x,2), B (-3,-4), C (7,-5) are collinear then find the value of x
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eq for line BC.....
x1=-3..........y1=-4
x2=7...........y2=-5
slope=(y2-y1)/(x2-x1)=(-5+4)/(7+3)=-1/10
equation...=y-y1=slope(x-x1)
y+4=(-1/10)*(x+3)
10y+40=-x-3
x+10y=-43.....①
coordinates of A=(x,2)
as the lines are collinear so value of x=x and y=2 will satisfy the eq.①
x+10*2=-43
x+20=-43
x=-63
x1=-3..........y1=-4
x2=7...........y2=-5
slope=(y2-y1)/(x2-x1)=(-5+4)/(7+3)=-1/10
equation...=y-y1=slope(x-x1)
y+4=(-1/10)*(x+3)
10y+40=-x-3
x+10y=-43.....①
coordinates of A=(x,2)
as the lines are collinear so value of x=x and y=2 will satisfy the eq.①
x+10*2=-43
x+20=-43
x=-63
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