Question

if the points (K, 3), (0,2) and (0,1) are collinear what is the value of k
please answer​

Answer 1

Answer:

1

Step-by-step explanation:

Ponits are collinear then, area of triangle equal to 0.

Now A(K,3), B(0,2), C(0,1).

Area of=1/2 {X2(Y2-Y3)+X2(Y3-Y1)+X3(Y1-Y2)=0

= 1/2{K(2-1)+0(1-3)+0(3-2) =0

= 2K/2=0

K=0

=

Answer 2

Answer:

Hope it helpful to you mate ☺