Question

If the points p(1,3) and q(-2,-1) lie on the graph of the line px+qy=5. find the values of p and q (urgenttttttttttttttttttttt)

Answer 1

px+qy=5
qy=-px+5
y= (-p/q)x + 5/q
therefore slope is -p/q

m(slope)=-1-3 / -2-1 = -4/-3 = 4/3

-p/q = 4/3
p=-4; q=3.


Another method,
y - y1 / y1 -y2 = x - x1 / x1 - x2

y-3/3+1 = x-1/1+2
y-3/4 = x-1/3
3y-9 = 4x-4
4x - 3y - 4 + 9 = 0
4x - 3y + 5 = 0
-4x+3y-5=0

Comparing with given equation, we get
p= -4; q= 3