If the points P (-2, 1), Q (a, 0), R (4, 1) and S (1, 2) are the vertices of a
parallelogram taken in order, find the value of ‘a’
Answers
Answered by
1
Answer:
Diagonals of a parallelogram bisect each other.
So the mid point of diagonal PR and mid point of diagonal QS coincide.
We have mid point formula,
P(X,Y)=(
2
x
1
+x
2
,
2
y
1
+y
2
)
It implies that
2
a+2
=
2
5+1
Or a+2=6
Or a=4
Similarly,
2
b+1
=
2
−11+15
Or b+1=4
Or b=3
Answered by
1
Answer:
Given
P(-2,1)
Q(a,0)
R(4,1)
S(1,2)
are given as vertices of paralleogram
so we will simply use distance formula here
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