Math, asked by RITIGAA14, 6 months ago

If the points P (-2, 1), Q (a, 0), R (4, 1) and S (1, 2) are the vertices of a

parallelogram taken in order, find the value of ‘a’​

Answers

Answered by Nivedita4209
1

Answer:

Diagonals of a parallelogram bisect each other.

So the mid point of diagonal PR and mid point of diagonal QS coincide.

We have mid point formula,

P(X,Y)=(

2

x

1

+x

2

,

2

y

1

+y

2

)

It implies that

2

a+2

=

2

5+1

Or a+2=6

Or a=4

Similarly,

2

b+1

=

2

−11+15

Or b+1=4

Or b=3

Answered by VarunDevMishra
1

Answer:

Given

P(-2,1)

Q(a,0)

R(4,1)

S(1,2)

are given as vertices of paralleogram

so we will simply use distance formula here

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