if the points p(5,3) and Q ( k,4) are on a circle with center O(2,-1) find 5he value of k
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Points P and Q are on the circle. That means the distance of both the points from the centre is same
Therefore,
OP = OQ
√(5 - 2)² + (3 -(-1))² = √(k - 2)² + (4-(-1))²
Squaring on both the sides cancels the roots.
(5-2)² + (3+1)² = (k-2)² + (4+1)²
3² + 4² = (k-2)² + 5²
9 + 16 = (k-2)² +25
25 - 25 = (k-2)²
(k-2)² = 0
k-2 = 0
k = 2.
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