Question

If the points P. Q(x,7), R. S(6,y) in this order divide the line segment joining a(2,p)and b(7,10) in 5 equal parts, find x, y and p.​

Answer 1

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AP = PQ = QR = RS = SB So, Q is the mid-point of A and S Then, x = (2 + 6)/ 2 = 8/2 = 4 7 = (y + p)/ 2 y + p = 14 ….. (1) Now, since S divides QB in the ratio 2: 1 So, p = 14 – 9 = 5 Therefore, x = 4, y = 9 and p = 5

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