Question

If the points P (x,y) is equidistant from L( 5,1) and M (-1,5), then the relation between x and y is ?

Answer 1

Step-by-step explanation:

Given :-

• P = (x, y)
• L = (5,1)
• M = (- 1, 5)
• PM = PL ------(1)

By using distance formula,

$\bf \: Distance \: BP = \sqrt{(- 1 - x) ^ 2 + (5 - y) ^ 2)} \\ \bf \: B P ^ 2 = 1 + x ^ 2 + 2x + 25 + y ^ 2 - 10y \\ \bf \: B P ^ 2 = 26 + x ^ 2 + y ^ 2 + 2x - 10y$

Since P is the midpoint.

$\pmb{ \: A P ^ 2 = B P ^ 2}$

$\bf \: x ^ 2 + y ^ 2 + 26 - 10x - 2y = x ^ 2 + y ^ 2 + 2x - 10y + 26 \\ \bf \: x ^ 2 - x ^ 2 + y ^ 2 - y ^ 2 + 26 - 26 - 10x + 2x = - 10y + 2$

$\bf - 12x = - 8y \\ \bf - 3x = - 2y \\ \bf \: 3x = 2y \\ \red{ \bf \: hence \: proved}$

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Answer 2

Answer:

this is correct answer

hope it dx