if the points (p2 ,0) and (0,q2 and (1,1 are collinear prove that1/p2+1/q2=1
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the area of triangle is zero, then the points are collinear.
Points are collinear.
Point are (p,o)(o,q)(i,q)
Δ=21[p(q−1)−0(1−0)+1(0−q)]
⇒21[p(q−1)−q]
⇒21[p(q−1)−q]
⇒21[pq−(p+q)]=o
⇒pq=p+q⇒pqp+q=1
⇒p1+q1=1
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