if the points (x,1) (1,2) and (0, y+1) are collinear
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1/x + 1/y =1
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Area of triangle = 0
x [ 2- ( y + 1)] + 1 ( y + 1 -1 ) + 0 ( 1 -2 )= 0
x - xy + y = 0
( divide by xy )
1/y -1 + 1/x = 0
1/y + 1/x = 1
Thus proved
x [ 2- ( y + 1)] + 1 ( y + 1 -1 ) + 0 ( 1 -2 )= 0
x - xy + y = 0
( divide by xy )
1/y -1 + 1/x = 0
1/y + 1/x = 1
Thus proved
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