If the points (x, y), (2, 3) & (−3, 4) are collinear then (a) x + y = 17 (b) x − y = 17 (c) x − 5y = 17 (d) x + 5y = 17
Answers
Answered by
2
Answer:
ANSWER
Given A,B,C are collinear and AB=BC
So, B is the midpoint of the line segment AC.
by using midpoint formula
x=(
2
x
1
+x
2
)andy=(
2
y
1
+y
2
)
So
2
5+x
=3
5+x=6
x=1
Also,
2
2+y
=4
2+y=8
y=6
Hence, C(x,y) is C(1,6)
Answered by
3
Answer:
equation of line joining (2,3),(-3,4) is
y-3=(4-3)/(-3-2)×(x-2)
y-3=1/5×(2-x)
5y-15=2-x
x+5y-17=0
since (x,y) and other points are collinear, (x,y) is the point on the line
x+5y=17
SO OPTION D IS CORRECT
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