If the points(x,y) is collinear with the points(a,0) and (0,b) prove that x/a + y/b=1
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If the three points A,B and C are collinear, then
slopes of any two pairs of points will be equal.
Now, apply slope formula to find the slopes of the respective pairs of points:
Slope of AB = -y/(a-x)
Slope of BC = b/(-a)
Slope of AC = (b-y)/(-x)
Slope of AB = Slope of AC
-y/(a-x) = (b-y)/(-x)
xy = (a-x) (b-y)
xy = ab -ay -bx + xy
ab = bx + ay
divide by ab on both sides,
1 = x/a + y/b
slopes of any two pairs of points will be equal.
Now, apply slope formula to find the slopes of the respective pairs of points:
Slope of AB = -y/(a-x)
Slope of BC = b/(-a)
Slope of AC = (b-y)/(-x)
Slope of AB = Slope of AC
-y/(a-x) = (b-y)/(-x)
xy = (a-x) (b-y)
xy = ab -ay -bx + xy
ab = bx + ay
divide by ab on both sides,
1 = x/a + y/b
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Let the points are A(x, y), B(a, 0) and C(0, b).
If the points A, B, C are collinear, then the area of the triangle will be equal to zero
=> (1/2)*{x(0 - b) + a(b - y) + 0(y - 0)} = 0
=> -bx + ab - ay = 0
=> bx + ay = ab
=> bx/ab + ay/ab = 1
=> x/a + y/b = 1
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