if the polinomials x^3+ax^2+5 and x^3-2x^2+a are divided by (x+2) leave the same remainder find the value of a
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a=-13/3
Step-by-step explanation:
zero of x+2=-2
p(x)=x^3+ax^2+5
=(-2)^3+a(-2)^2+5
=-8+4a+5
=-3+4a
p(x)=x^3-2x^2+a
=(-2)^3-2(-2)^2+a
=-8-8+a
=-16+a
-3+4a=-16+a
4a-a=-16+3
3a=-13
a=-13/3
Thanks!
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