Question

if the polynomial 2 x cube + 8 x square + 3 x minus 5 and x cube + x square - 4 x + a leave the same remainder when divided by x minus 2 find the value of a

Answer 1

mark me as brainlist please
find this attachment

Answer 2

it is given that when it is divided by x-2 it gives same remainder so,
x-2=0
x=2

then, we have
$2 {x}^{3} + 8 {x}^{2} + 3x - 5 = {x}^{3} + {x}^{2} - 4x + a$
$2 \times {2}^{3} + 8 \times {2}^{2} + 3 \times 2 - 5 = {2}^{3} + {2}^{2} - 4 \times 2 + a$
$2 \times 8 + 8 \times 4 + 6 - 5 = 8 + 4 - 8 + a$
$16 + 32 + 6 - 5 = 4 + a$
$49 = 4 + a$
$49 - 4 = a$
$a = 45$
so,
a=45 is ur answer....
hope this help u mate