Question

If the polynomial 2x cube+ax square +3x-5 and x cube +x square -4x + a leaves the same remainder when divided by x-4 then find the value of a.

Answer 1

$(2 {x}^{3} + {ax}^{2} + 3x - 5) \div x - 4 \\ ({x}^{3} + {x}^{2} - 4x + a) \div x - 4$

a = -8