Math, asked by gauravkumar250505, 9 months ago

if the polynomial -2X² + Kx + √2 has a root 1,then what is the value of k​

Answers

Answered by ekta22001
0

Step-by-step explanation:

Placing the value of x in the equation that is 1.

 - 2 {x}^{2}  + kx +  \sqrt{2}  = 0 \\   - 2( {1}^{2} ) + k \times 1 +  \sqrt{2}  = 0 \\  - 2 + k +  \sqrt{2 }  = 0 \\ k +  \sqrt{2}  = 2 \\ k = 2 -  \sqrt{ 2}

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