Question

if the polynomial 2x³+ax²+3x-5 and x³+x²-2x+2a leave the same reminder when divided by x-3. Find the value of a​

Answer 1

Answer:

a=4

Step-by-step explanation:

given:2x³+ax²+3x-5

x-3=0

then,x=3

2(3)³+a(3)²+3(3)-5

2(27)+a(9)+9-5

54+9a+4

9a+58

then

x³+x²-2x+2a

(3)³+(3)²-2(3)+2a

27+9-6+2a

30+2a

equating 1 and 2

9a+58=30+2a

9a-2a=30-58

7a=28

a=28/7

a=4