Question

if the polynomial 2x³+ax²+3x-5 andx³+x²-4x+a leave the same remainder when divided by x-2 find the value of a​

Answer 1

Step-by-step explanation:

Given

2x³+ax²+3x-5 andx³+x²-4x+a leave the same remainder when divided by x-2

now

x-2=0

x= 2

p(x) = 2x³+ax²+3x-5 = x³+x²-4x+a

p(2) = 2(2)³+a(2)²+3(2)-5 = (2)³+(2)²-4(2)+a

= 16+4a+6-5 = 8+4-8+a

= 17+4a = 4+a

= 4a-a = 4-17

3a = 13

a = 13/3