if the polynomial 3x^3+ax^2+3x+5 and 4x^3+ x^2-2a+a leave the same remainder when dividad by x-2.find the value of a,also find the remainder in each case
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X-2=0(zero of polynomial)
X=2
Put both equation equal as they both leaves same remainder and put x=2
Then u will get
3×8+a×4+6+5=4×8+4-2a+a
24+4a+11=36-a
35+4a=36-a
4a+a=36-35
5a=1
a=1/5
X=2
Put both equation equal as they both leaves same remainder and put x=2
Then u will get
3×8+a×4+6+5=4×8+4-2a+a
24+4a+11=36-a
35+4a=36-a
4a+a=36-35
5a=1
a=1/5
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