Question

if the polynomial 3x^4+ax^2+3x+5 and 4x^3+x^2-2x+a leave the same remainder when divided by (x-2) find the value of a also find the remainder in each case​

Answer 1

Answer:

Remainder = 23

and

a = -9

Step-by-step explanation:

When

3x^4+ax^2+3x+5 is divided by x-2

We get,

Remainder= 59+4a

Similarly when  

4x^3+x^2-2x+a is divided by x-2

We get,

Remainder= a+ 32

Since the remainders of both the polynomials are equal  

We have,

59+4a = a+ 32

4a – a = 32 – 59

3a = -27

We have,  a = -9

By putting the value of a in the remainder, a+ 32

We have remainder= 23

Similarly, by putting the value of a in the remainder, 59+4a

We have remainder= 23