if the polynomial(3xcube + axsquare + 3x +5) and (4xcube + xsquare -2x + a) leave the same remainder when divided by x-2 then find the value of a and also remainder in both case
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After dividing 3x³+ax²+3x+5 by x-2
and 4x³+x²-2x+a by x-2
remainder will be 2ax+ 35 and 32 +a
according to question,
2ax+ 35=32+a
a=3÷(1-2x)
then remainder will be (35-64x)÷1-2x
and 4x³+x²-2x+a by x-2
remainder will be 2ax+ 35 and 32 +a
according to question,
2ax+ 35=32+a
a=3÷(1-2x)
then remainder will be (35-64x)÷1-2x
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