Question

If the polynomial 4x³-3x²+ax-4 and x⁴-x³+5ax+20 when divided by x-2 leaves the same remainder, find the value of a.

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Answer 1

f (2)= 32 -12+2a-4

=16+2a

g (2)=16-8-10a+2a

=28-10a

f (2)=g (2)

16+2a=28-10a

12a=12

a=1