Question

If the polynomial 6x*4+8x*3+17x*2+21x+7 is divided by another polynomial 3x*2+4x+1 , the remainder comes out to be (ax+b) , find a and b

Answer 1

Hii friend,

P(X) = 6X⁴+8X³+17X²+21X+7

G(X) = 3X²+4X+1

On dividing polynomial P(X) by G(X) we get,

Remainder = X+2

And,

Quotient = 2X²+5

According to question when we Divide the polynomial P(X) by G(X) then Remainder comes (AX+B)

Therefore,

Remainder = X+2

Coefficient of X is 1 and constant term is 2

Therefore,

A =1 and B = 2

HOPE IT WILL HELP YOU..... :-)

Answer 2

When 6x^4+8x^3+17x^2+21x+7 is divided by 3x^2+4x+1 then quotient is we 2x^2+5 and remainder is x+2


A=1 and b=2