Question

if the polynomial 6x^4 +8x^3+17x^2+21x+7 is divided by 3x^2+4x+1 remainder ax+b find a& b​

Answer 1

Step-by-step explanation:

If the expression 6 x^{4}+8 x^{3}+17 x^{2}+21 x+7 is ‘divided another one’ 3 x^{2}+4 x+1, ‘remainder’ will be “(ax + b)”.

Thus, the division of both the ‘equations’ are derived in below attached image.

Therefore, \mathrm{x}+2=\mathrm{ax}+\mathrm{b}

\begin{aligned} \mathrm{x} &=\mathrm{ax} \\ \frac{x}{x} &=a \end{aligned}

a = 1 and b = 2

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Answer 2

Step-by-step explanation:

If the expression 6 x^{4}+8 x^{3}+17 x^{2}+21 x+7 is ‘divided another one’ 3 x^{2}+4 x+1, ‘remainder’ will be “(ax + b)”.

Thus, the division of both the ‘equations’ are derived in below attached image.

Therefore, \mathrm{x}+2=\mathrm{ax}+\mathrm{b}

\begin{aligned} \mathrm{x} &=\mathrm{ax} \\ \frac{x}{x} &=a \end{aligned}

a = 1 and b = 2