Question

if the polynomial are ax³+4x³+3x-4x³+a are divided by (x-3)leave the remainder then find the value of a​

Answer 1

Step-by-step explanation:

please mark as BRAINEST

Answer 2

Answer:

$let \: \: p(x) = {ax}^{3} + {4x}^{3} + 3x - {4x}^{3} + a = 0$

Now,

$(x - 3) = 0$

$x = 3$

Putting the value of x in p(x) :

$p(x) = {ax}^{3} + {4x}^{3} + 3x - {4x}^{3} + a = 0$

$a {(3)}^{3} + 4 {(3)}^{3} + 3(3) - 4 {( 3)}^{3} + a = 0$

$27a + 108 + 9 - 108 + a = 0$

$27a + a + 9 = 0$

$28a = - 9$

a = -9/28

Ans. -9/28

Hope it helps.