Question

If the polynomial ax^3+3x^2-13 and 2x^3-5x+a are divided by(x-2) leave same remainder find a​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$\huge{\boxed{\rm{\red{x=1}}}}$

Step-by-step explanation:

Given polynomials are :-

p(x)=ax³+3x²-13 -----(1)

g(x)=2x³-5x+a ------(2)

Given divisor =(x-2)

Used theorem:-

Remainder theorem:-

Let p(x) be a polynomial of the degree is greater than or equal to 1 ,If p(x) is divided by a linear polynomial (x-a) then the remainder is p(a).

p(2)=a(2)³+3(2)²-13

=>8a+12-13

=>8a-1------(3)

g(2)=2(2)³-5(2)+a

=>16-10+a

=>a+6----(4)

They leaves same remainder then

(3)=(4)

=>8a-1=a+6

=>8a-a=6+1

=>7a=7

=>a=7/7=1

Therefore,a=1

The value of a is 1