if the polynomial ax^3+4x^2+3x-4 and x^3-4x+a leave the same remainder when divided by x-3 find the value of a
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Step-by-step explanation:
Let p(x) = ax3 + 4x2 + 3x – 4 and q(x) = x3 – 4x + a be the given polynomials.
When p(x) and q(x) are divided by (x – 3) the remainder are p(3) and q(3) respectively.
p(3) = q(3) given
a(3)3 + 4(3)2 + 3 × 3 – 4 = 33 – 4 × 3 + a
⇒ 27a + 36 + 9 – 4 = 27 – 12 + a
⇒ 26a = 15 – 41
⇒ 26a = - 26
∴ a = - 26/26 = - 1
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