If the polynomial ax³ + 3x² -13 and 2x³ – 5x + a when divided by (x – 2) leave the same remainder, find the Value of a
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Answer:
a= 1
Step-by-step explanation:
f(x) = ax³ + 3x² -13
x-2=0, x=2
When we substitute x=2 in f(x)
f(2)=a(2)^3 + 3(2)^2 -13 = 8a + 12 - 13 = 8a - 1
g(x)= 2x³ – 5x + a
X=2
g(2)= 2(2)^3 - 5(2) + a = 16 - 10 + a = 6 + a
Since it is given that when the equations are divided by (x-2) they leave the same remainder,hence we can equate the remainders of the two equations.
8a-1 = 6 + a
8a-a = 6+1
7a= 7
a=1
Hope it helps!
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