If the polynomial ax³+4x²+3x-4 and x³-4x+a leave the same remainder when divided by(x-3),find a
Answers
Answered by
6
Answer:
a = -1
Step-by-step explanation:
Let p₁(x) = ax³ + 4x² + 3x - 4 and p₂(x) = x³ - 4x + a
Given that both leave the same remainder divided by (x - 3).
∴ p₁(3) = p₂(3)
⇒ a(3)³ + 4(3)² + 3(3) - 4 = (3)³ - 4(3) + a
⇒ 27a + 36 + 9 - 4 = 27 - 12 + a
⇒ 26a + 41 = 15
⇒ 26a = -26
⇒ a = -1
Therefore, the value of a = -1
Hope it helps!
Answered by
1
Answer:
a=-22/13
Step-by-step explanation:
Attachments:
SANJAILION:
answer is -1
26a=15-41=-26,so a=-26/26=1, so answer is a=-1
Similar questions