Question

if the polynomial ax3+bx-c is exactly divisible by X2+bx+c then find ab value
​

Answer 1

Answer:

Step-by-step explanation:

f f(x) is divisible by g(x), then the "remainder" of a long division would equal zero.

The remainder after dividing f(x) by g(x) is  

[(ab² - ac + b)x + c(ab - 1)]/(x² + bx + c)

For the numerator to equal zero, both terms in parentheses have to be equal to zero

ab² - ac + b = 0 and ab - 1 = 0

ab = 1.......(i)

or a=1/b

 

ab² - ac + b = 0

ac = ab² + b

ab = 1...........(from (i))

ac = b + b = 2b c=2b/a c = 2b/(1/b).......substituting value of a or c = 2b2...........

Please mark it as brainiest answer .............