Question

If the polynomial ax3 +bx2 - c is divisible by x2 + bx +c then ab = ?

Answer 1

If f(x) is divisible by g(x), then the "remainder" of a long division would equal zero.

The remainder after dividing f(x) by g(x) is 

[(ab² - ac + b)x + c(ab - 1)]/(x² + bx + c)

For the numerator to equal zero, both terms in parentheses have to be equal to zero

ab² - ac + b = 0 and ab - 1 = 0

ab = 1.......(i)

or a=1/b

  
ab² - ac + b = 0

ac = ab² + b

ab = 1...........(from (i))

ac = b + b = 2b c=2b/a c = 2b/(1/b).......substituting value of a or c = 2b2...........

Please mark it as brainiest answer .............

Answer 2

Well the given statement is wrong let's do some corrections in statement :

p(x) = ax³+bx-c

For Full Solution Refer To The Above Attachment !!

Here :

p(x) = ax³+bx-c

g(x) = x²+bx+c

Then it is the given factor so it will make the remainder = 0.

By using the long division method we can find out the remainder.

Then put the remainder= 0.

And find ab .

The required value of ab = 1.