Question

if the polynomial az^3 + 4z^2 + 3z - 4 and z^3 - 4z + a leave the same remainder when divided by z-3. Find the value of a.

give the correct answer

don't give unnecessary answers.

PLEASE
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Answer 1

27a+36+9-4

27a+41=0

27a=-41

a= -41/27

Answer 2

Answer:

a= -1

Step-by-step explanation:

First divide $az^{3} +4z^{2} +3z-4$ by z-3

On division, you will the remainder= 41+27a            .................(i)

Then divide $z^{3} -4z+a$ by z-3.

On division, you'll get the remainder as 15+a           ................(ii)

Since according to questions both the remainders are equal, therefore on equating (i) and (ii), we will get

    15+a      =   41+27a

⇒  15-26a  =   41

⇒   -26a    =   26

⇒           a = -1

∴ a= -1

Hope it helped you!!