If the polynomial az3+4z2+3z-4 and z3-4z+a leave the same remainder when divided by
(z-3) , then find value of ‘a’.
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Step-by-step explanation:
az^3 +4z^2 +3z -4 and z^3 -4z +a leave the same reminder when divided by z-3.
Hence, [a (3)^3 +4(3)^2 +3×3 -4] = [3 ^3 -43 +a]
=>[ 27 a+36 +9-4] = [27- 12 +a ]
= > 26 a = -26
=> a = -1
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