Question

If the polynomial bx³+4x²+3x-4 and x³-4x leave the same remainder, when divided by x - 3. Find the value of b.​

Answer 1

Answer:

b= -26/27

Step-by-step explanation:

Let,

f(x)=bx³+4x²+3x-4

p(x)=x³-4x

g(x)=x-3

if g(x)=0 then x=3

=> Dividing f(x) by g(x) remainder(R₁)=f(3)=b×3³+4×3²+3×3-4=27b+41 --------(i)

=> Dividing p(x) by g(x) remainder(R₂)=p(3)=3³-4×3=15--------(ii)

According to Question,

R₁=R₂

=>27b+41=15 (from (i) & (ii))

=>27b=15-41

=>27b= -26

Hence,value of b= -26/27