if the polynomial bz^3+4z^2+3z-4 and z^3-4z+b leaves the same remainder when divide by z-3 find the value of b
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Answer
b = -1
Step-by-step explanation
Answered by
0
Answer:
b= -1
Step-by-step explanation:
bcoz; when we divide the first equation by z-3 by using long division method
the remainder will be 27b+41
and when we divide the second equation by z-3
the remainder will be b+15
equating the remainders
27b+41= b+15
26b= -26
b= -1
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