Question

If the polynomial f(x)= ax3 + bx -c is divisible by x2+ bx + c then ab = ?

Answer 1

${\pmb{\frak{\underline \red{Given:-}}}}$

• ➠ If the polynomial f(x)= ax3 + bx -c is divisible by x2+ bx + c .

${\pmb{\frak{\underline\red{Find:-}}}}$

• ➠ Find the " ab "

${\pmb{\frak{\underline\red{Solution-}}}}$

• ➠ It's remainder is " 0 "

$\red\bigstar\rm\underline{ \: So,}$

$\longmapsto\rm{ ( b - ac - an ) x = abc}$

• it is equal to " 0 ".

$\longmapsto\rm \boxed{ \rm \red {x = \frac{abc}{b - \: ac \: - ab} }}$

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$\bf \underline{Learn More :}$

$\begin{gathered}\boxed{\begin{gathered}{\underline{\textbf{square \: roots \: formula :}}}\\\\ \sf {\dashrightarrow{(a \: + \: b) ^{2} = {a}^{2} + {b}^{2} + 2ab}}\\\\\\ \sf {\dashrightarrow{ \: \:( \: a \: - \: b) ^{2} = {a}^{2} + {b}^{2} - 2ab {}}}\\\\\\ \end{gathered}}\end{gathered}$

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@Shivam

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