Math, asked by sowmilakshsi, 10 months ago

If the polynomial f (X)=x^4-6x^3+16x^2-25x+10 is divided by another polynomial x^2-2x+k, the remainder comes out to be X+a, find k and a

Answers

Answered by knjroopa
1

Step-by-step explanation:

Given If the polynomial f (X)=x^4-6x^3+16x^2-25x+10 is divided by another polynomial x^2-2x+k, the remainder comes out to be X+a, find k and a

  • We have f(x) = x^4 – 6x^3 + 16x^2 – 25x + 10
  •  Also divisor = x^2 – 2x + k
  • Remainder = x + a
  • Subtracting remainder from f(x) we get
  • x^4 – 6x^3 + 16x^2 – 25 x + 10 – (x + a)
  • x^4 – 6x^3 + 16x^2 – 26x + 10 – a = f(y)
  • now f(y) is divisible by divisor x^2 – 2x + k
  • So we get
  •                                           x^2 – 4x + (8 – k)
  • ----------------------------------------------------------------------------------------
  •    x^2 – 2k + k) x^4 – 6x^3 + 16x^2 – 26x + 10 – a
  •                            x^4 – 2x^3 + kx^2
  •                     --------------------------------------------------------------------------
  •                                    -4x^3 + (16 + k)x^2 – 26 x + 10 – a
  •                                     -4x^3 + 8x^2           - 4kx
  •                           -------------------------------------------------------------------------
  •                                               (8 – k)x^2 – (26 – 4k)x + 10 – a
  •                                                (8 – k)x^2 – (16 – 2k)x + (8k – k^2)
  •                                    ----------------------------------------------------------------------
  •                                                                (- 10 + 2k)x + (10 – a – 8k + k^2)
  • Now remainder is zero
  •              -(10 + 2k)x + (10 – a – 8k + k^2) = 0  
  • Now – 10 + 2k = 0 and 10 – a – 8k + k^2 = 0
  •        So k = 5 and 10 – a – 8(5) + 5^2 = 0
  •                           10 – a – 40 + 25 = 0
  •                             Or a = - 5

Therefore k = 5 and a = - 5

Reference link will be

https://brainly.in/question/2159029

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