if the polynomial f(X)= x cube + b x minus C is divisible by the polynomial g(X) =X square + bx + c then find the value of a b
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Answer:
f(x)=ax3+bx−c
g(x)=x2+bx+c
f(x) divides g(x) means roots of g(x) are also roots of f(x)
Let p,q be the roots of g(x) and p,q,r be the roots of f(x)
g(x):
Sum of the roots = Coefficient of x =p+q=−b
Product of the roots =pq=c
f(x):
Sum of the roots = Coefficient of x2=p+q+r=0
⟹−b+r=0⟹r=b
Product of the roots = pqr=ca
Substituting r=b and pq=c in the above:
⟹c.b=ca⟹⟹ab=1
Ans: ab=1
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