if the polynomial is az power 3 + 4z power 2 + 3z - 4 and z power 3 - 4z +a leave the same remainder when divided by z- 3 find the value of a
Answers
Answered by
2
Given that az3+ 4z2 + 3z - 4and z3 - 4z + a leave the same remainder when divided by z - 3
Hence [a(3)3+ 4(3)2 + 3(3) - 4] = [(3)3 - 4(3) + a]
⇒ [27a+ 36 + 9 - 4] = [27 -12 + a]
⇒ [27a+ 41] = [15 + a]
⇒ 26a = – 26
Hence a = – 1
Hence [a(3)3+ 4(3)2 + 3(3) - 4] = [(3)3 - 4(3) + a]
⇒ [27a+ 36 + 9 - 4] = [27 -12 + a]
⇒ [27a+ 41] = [15 + a]
⇒ 26a = – 26
Hence a = – 1
Similar questions