Question

if the polynomial kx^3+4x^2+3x-4 and x^3-4x+k leave the same remainder when divided by (x-3) then find the value of k

Answer 1

Solution :-

p(x) = kx^3+4x^2+3x-4 , p(x) = x^3 -4x+k
ģiven p(3) = 0

p(3)=k(3)^3+4(3)^2+3.3-4=0 , p(3)=(3)^3-4.3+k=0

27k+36+9-4 =0 , 27 -12 +k =0

[ k = 41/27 ] ans , [ k = 15]ans

i hope its helpfull of u

Answer 2

Step-by-step explanation:

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