Question

If the polynomial p(x)=2x cube-5x+4 then find the value of p(2) and p(0).​

Answer 1

Answer:

Hey,

Given :

2 and 0 are the two zeros of the given Polynomial.

P(X) = 2X³ - 5X² + AX + B

P(2) = 2 × (2)³ - 5 × (2)² + A × 2 + B

=> 2 × 8 - 5 × 4 + 2A + B

=> 16 - 20 + 2A + B = 0

=> 2A + B -4 = 0

=> 2A + B = 4 -------(1)

Also,

X = 0

P(0) = 2 × (0)³ - 5 × (0)² + A × 0 + B

=> 2 × 0 + 5 × 0 + 0 + B

=> B = 0

Putting the Value of B in equation (1)

2A + B = 4

2A + 0 = 4

2A = 4

A = 4/2

A = 2.

Hope it helps u  :))

Step-by-step explanation:

Answer 2

p(x) = 2x³-5x+4 (Given)

When, it is given, p(2), p(0) or some other number, that means to put the number at the places of that alphabet, then :

p(2) = 2(2)³-5×2+4

p(2) = 2×8-10+4

p(2) = 16 -10+4

p(2) = 10

The value of p(2) will be 10.

p(0) = 2(0)³-5×0+4

p(0) = 0-0+4

p(0) = 4

The value of p(0) will be 4.