if the polynomial p x is equal to 3 x cube minus 2 x square + x + 1 then coefficient of the x cube is
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Step-by-step explanation:
Given p(x)=x³-2x²-5x+6
p(3)=27-18-15+6=0
p(-2)=-8-8+10+6=0
p(1)=1-2-5+6=0
Hence the given numbers are the zeroes of the given cubic polynomial.
Let the coefficients be q,r,s,t and roots a,b,c
Relation between roots
sum of the roots=a+b+c=-r/q=-(-2/1)=2=3+(-2)+1
product of the roots=abc=-t/q=-6=3×-2×1
sum of the products of pair of roots=ab+bc+ca=s/q=-5=3(-2)+(-2)1+1(3)
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