Question

if the polynomial p(x)=x^4-2x^3+3x^2-ax+8 is divided by (x-2) it leaves of remainder is 10​

Answer 1

Step-by-step explanation:

let (x-2)=0

∴x=2

p(2)=(2)^4-2(2)^3+3(2)^2-a(2)

10=16-16+12-2a

2a=2

a=2

hope this helps you!! :)

Answer 2

Answer:

1

Step-by-step explanation:

p(x)=x 4 -2x 3 3x 2 -ax

x = 2

P(2)=(2)^4-2(2)^3+3(2)^2-a(2)

10=16-16+12-2a

2a=2

a=1