Question

if the polynomial p(x)=x¹⁰⁰⁰+ax+9 has a factor(x+1,then a equal​

Answer 1

Answer:

Answer =10

Step-by-step explanation:

p(x) =x^1000+ax+9

divided (x+1)

therefore p(x) = -1

p(-1)= -1^1000+a(-1)+9=0

= 1-a+9=0

= -a= -9-1

= 10

Answer 2

Answer:

$\huge{\boxed{\rm{\red{a=10}}}}$

Step-by-step explanation:

Given :-

the polynomial p(x)=x¹⁰⁰⁰+ax+9 has a factor(x+1)

To find:-

The value of a

Solution:-

Given polynomial p(x)=x¹⁰⁰⁰ +ax+9

given factor =(x+1)

Used Concept:-

Factor theorem:-

Let p(x) be a polynomial of the degree is greater than or equal to one ,If (x-a) is another linear polynomial then (x-a) is a factor if p(a)=0

Since (x+1) is a factor then

Now ,x+1=0=>x=-1

p(-1)=0

=>(-1)¹⁰⁰⁰+a(-1)+9=0

=>1-a+9=0

=>-a+10=0

=>a=10

Answer:-

The value of a=10