Question

if the polynomial p(X)= x²+ax²+3x+2 is divisible by ( X+a) then the value of a is:
​

Answer 1

Answer:

p(X)= x²+ax²+3x+2

x+a = 0

x= -a

p(-a)= (-a)²+a(-a)²+3(-a)+2

p(-a)= a² + a(a²) - 3a +2

p(-a)= a² + a³ - 3a + 2

0= a² + a³ - 3a + 2