If the polynomial p(x)=x4-2x³+3x²-ax+8 is divided by (x-2), it leaves a reminder 10. find the value of 'a'.
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Answer:
14
Explanation:
The remainder when p is divided by x−1 is is 6 , therefore (remainder theorem)
p(1)=6 .
The other condition, can be written
p(−1)=14 .
These equations are written in terms of a and b as
1−2+3−a+b=6
1+2+3+a+b=14 .
or
−a+b=4
a+b=8 ,
and hence
a=2
b=6 .
The remainder when p is divided by x−2 is (remainder theorem again)
p(2)=16−16+12−4+6=14 .
Therefore, the remainder is 14.
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