if the polynomial p(x)= x⁴-2x³+3x²-ax+8 is divided by x-2, it leaves a remainder 10. Find the value of a ?
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Answers
AnswEr :
When p(x) = x⁴ - 2x³ + 3x² - ax + 8 divided by (x - 2). It leaves a remainder 10.
We've to find the value of a.
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⠀⠀⠀⠀⠀ ⠀Any expression which have more than two algebraic terms is know as Polynomials.
⠀Types of polynomials :
- Monomial
- Binomial
- Trinomial
Monomial : It contains only one term.
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Binomial : It contains two terms.
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Trinomial : It contains three terms.
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Step-by-step explanation:
Given that, p(x)= x⁴-2x³+3x²-ax+8 is divided by x-2, it leaves a remainder 10.
We have to find the value of a.
From above data p(x) is 10 and value of x is 2 as x - 2 = 0, x = 2.
Simply substitute the value of p(x) and x in x⁴ - 2x³ + 3x² - ax + 8
→ 10 = (2)⁴ - 2(2)³ + 3(2)² - a(2) + 8
Solve the power,
→ 10 = 16 - 2(8) + 3(4) - 2a + 8
→ 10 = 16 - 16 + 12 - 2a + 8
→ 10 = 12 + 8 - 2a
→ 10 = 20 - 2a
→ 2a = 20 - 10
→ 2a = 10
Divide by 2 on both sides,
→ 2a/2 = 10/2
On solving we get,
→ a = 5
Hence, the value of a is 5.