Question

if the polynomial x^2-5x-3a and ax^2-5x-7 leave the same remainder when divided by x-1, find the value of a​

Answer 1

x-1)x²-5x-3a(x-4

x²-1x

------------------

0 -4x-3a

-4x+4

-------------

0 -4-3a--------(1)

again

x-1)ax²-5x-7(ax+a-5

ax²-ax

---------------

0+ax-5x

ax-a

---------------

0-5x+a
-5x+5
--------------
0 +a-5-7 -------2

-4-3a = +a-12
3a+a =12-4
4a =8
a=8/4
a=2
your ans is 2.
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