if the polynomial x^2-5x-3a and ax^2-5x-7 leave the same remainder when divided by x-1, find the value of a
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x-1)x²-5x-3a(x-4
x²-1x
------------------
0 -4x-3a
-4x+4
-------------
0 -4-3a--------(1)
again
x-1)ax²-5x-7(ax+a-5
ax²-ax
---------------
0+ax-5x
ax-a
---------------
0-5x+a
-5x+5
--------------
0 +a-5-7 -------2
-4-3a = +a-12
3a+a =12-4
4a =8
a=8/4
a=2
your ans is 2.
mark brainly.
x²-1x
------------------
0 -4x-3a
-4x+4
-------------
0 -4-3a--------(1)
again
x-1)ax²-5x-7(ax+a-5
ax²-ax
---------------
0+ax-5x
ax-a
---------------
0-5x+a
-5x+5
--------------
0 +a-5-7 -------2
-4-3a = +a-12
3a+a =12-4
4a =8
a=8/4
a=2
your ans is 2.
mark brainly.
randhirkumar47:
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