Question

if the polynomial x^3-6x^2+ax+3 leaves a remainder 7 when it is divided by x-1

Answer 1

x^3-6x^2+ax+3
f(x)=f(1)
=1^3-6*1^2+a*1+3
=1-6+a+3
=a-2=7
a=7+2
a=9
Your answer is 9.