if the polynomial x³+ax²+5 and x³-2x²+a are divided by (x+2) leave the same remainder, find the value of a.
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Let x3+ax2+5 =p (x)
X3-2x^+a=f (x)
According to remainder theorm
P (x)=f (x)
So x+2 =0
X=-2
P (x)=-2cube+a×2square+5
13+4 a. .
F (x)=x3-2x^+a
8-8+a
So it's only a
13+4a=a
13=-3a
a=13/3
4.333...
X3-2x^+a=f (x)
According to remainder theorm
P (x)=f (x)
So x+2 =0
X=-2
P (x)=-2cube+a×2square+5
13+4 a. .
F (x)=x3-2x^+a
8-8+a
So it's only a
13+4a=a
13=-3a
a=13/3
4.333...
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